Integrand size = 17, antiderivative size = 122 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=-\frac {3 b \left (2 c^2 d+e\right ) x \sqrt {1-c^2 x^2}}{32 c^3}-\frac {b x \sqrt {1-c^2 x^2} \left (d+e x^2\right )}{16 c}+\frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}+\frac {b \left (8 c^4 d^2+8 c^2 d e+3 e^2\right ) \arcsin (c x)}{32 c^4 e} \]
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Time = 0.06 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {4814, 427, 396, 222} \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}+\frac {b \arcsin (c x) \left (8 c^4 d^2+8 c^2 d e+3 e^2\right )}{32 c^4 e}-\frac {b x \sqrt {1-c^2 x^2} \left (d+e x^2\right )}{16 c}-\frac {3 b x \sqrt {1-c^2 x^2} \left (2 c^2 d+e\right )}{32 c^3} \]
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Rule 222
Rule 396
Rule 427
Rule 4814
Rubi steps \begin{align*} \text {integral}& = \frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}+\frac {(b c) \int \frac {\left (d+e x^2\right )^2}{\sqrt {1-c^2 x^2}} \, dx}{4 e} \\ & = -\frac {b x \sqrt {1-c^2 x^2} \left (d+e x^2\right )}{16 c}+\frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}-\frac {b \int \frac {-d \left (4 c^2 d+e\right )-3 e \left (2 c^2 d+e\right ) x^2}{\sqrt {1-c^2 x^2}} \, dx}{16 c e} \\ & = -\frac {3 b \left (2 c^2 d+e\right ) x \sqrt {1-c^2 x^2}}{32 c^3}-\frac {b x \sqrt {1-c^2 x^2} \left (d+e x^2\right )}{16 c}+\frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}+\frac {\left (b \left (8 c^4 d^2+8 c^2 d e+3 e^2\right )\right ) \int \frac {1}{\sqrt {1-c^2 x^2}} \, dx}{32 c^3 e} \\ & = -\frac {3 b \left (2 c^2 d+e\right ) x \sqrt {1-c^2 x^2}}{32 c^3}-\frac {b x \sqrt {1-c^2 x^2} \left (d+e x^2\right )}{16 c}+\frac {\left (d+e x^2\right )^2 (a+b \arccos (c x))}{4 e}+\frac {b \left (8 c^4 d^2+8 c^2 d e+3 e^2\right ) \arcsin (c x)}{32 c^4 e} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.07 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\frac {1}{2} a d x^2+\frac {1}{4} a e x^4-\frac {b d x \sqrt {1-c^2 x^2}}{4 c}+b e \sqrt {1-c^2 x^2} \left (-\frac {3 x}{32 c^3}-\frac {x^3}{16 c}\right )+\frac {1}{2} b d x^2 \arccos (c x)+\frac {1}{4} b e x^4 \arccos (c x)+\frac {b d \arcsin (c x)}{4 c^2}+\frac {3 b e \arcsin (c x)}{32 c^4} \]
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Time = 0.89 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.32
method | result | size |
parts | \(\frac {a \left (e \,x^{2}+d \right )^{2}}{4 e}+\frac {b \left (\frac {c^{2} e \arccos \left (c x \right ) x^{4}}{4}+\frac {\arccos \left (c x \right ) d \,c^{2} x^{2}}{2}+\frac {c^{2} \arccos \left (c x \right ) d^{2}}{4 e}+\frac {c^{4} d^{2} \arcsin \left (c x \right )+e^{2} \left (-\frac {c^{3} x^{3} \sqrt {-c^{2} x^{2}+1}}{4}-\frac {3 c x \sqrt {-c^{2} x^{2}+1}}{8}+\frac {3 \arcsin \left (c x \right )}{8}\right )+2 d \,c^{2} e \left (-\frac {c x \sqrt {-c^{2} x^{2}+1}}{2}+\frac {\arcsin \left (c x \right )}{2}\right )}{4 c^{2} e}\right )}{c^{2}}\) | \(161\) |
derivativedivides | \(\frac {\frac {a \left (c^{2} e \,x^{2}+c^{2} d \right )^{2}}{4 c^{2} e}+\frac {b \left (\frac {\arccos \left (c x \right ) c^{4} d^{2}}{4 e}+\frac {\arccos \left (c x \right ) c^{4} d \,x^{2}}{2}+\frac {e \arccos \left (c x \right ) c^{4} x^{4}}{4}+\frac {c^{4} d^{2} \arcsin \left (c x \right )+e^{2} \left (-\frac {c^{3} x^{3} \sqrt {-c^{2} x^{2}+1}}{4}-\frac {3 c x \sqrt {-c^{2} x^{2}+1}}{8}+\frac {3 \arcsin \left (c x \right )}{8}\right )+2 d \,c^{2} e \left (-\frac {c x \sqrt {-c^{2} x^{2}+1}}{2}+\frac {\arcsin \left (c x \right )}{2}\right )}{4 e}\right )}{c^{2}}}{c^{2}}\) | \(172\) |
default | \(\frac {\frac {a \left (c^{2} e \,x^{2}+c^{2} d \right )^{2}}{4 c^{2} e}+\frac {b \left (\frac {\arccos \left (c x \right ) c^{4} d^{2}}{4 e}+\frac {\arccos \left (c x \right ) c^{4} d \,x^{2}}{2}+\frac {e \arccos \left (c x \right ) c^{4} x^{4}}{4}+\frac {c^{4} d^{2} \arcsin \left (c x \right )+e^{2} \left (-\frac {c^{3} x^{3} \sqrt {-c^{2} x^{2}+1}}{4}-\frac {3 c x \sqrt {-c^{2} x^{2}+1}}{8}+\frac {3 \arcsin \left (c x \right )}{8}\right )+2 d \,c^{2} e \left (-\frac {c x \sqrt {-c^{2} x^{2}+1}}{2}+\frac {\arcsin \left (c x \right )}{2}\right )}{4 e}\right )}{c^{2}}}{c^{2}}\) | \(172\) |
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Time = 0.25 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.84 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\frac {8 \, a c^{4} e x^{4} + 16 \, a c^{4} d x^{2} + {\left (8 \, b c^{4} e x^{4} + 16 \, b c^{4} d x^{2} - 8 \, b c^{2} d - 3 \, b e\right )} \arccos \left (c x\right ) - {\left (2 \, b c^{3} e x^{3} + {\left (8 \, b c^{3} d + 3 \, b c e\right )} x\right )} \sqrt {-c^{2} x^{2} + 1}}{32 \, c^{4}} \]
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Time = 0.34 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.30 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\begin {cases} \frac {a d x^{2}}{2} + \frac {a e x^{4}}{4} + \frac {b d x^{2} \operatorname {acos}{\left (c x \right )}}{2} + \frac {b e x^{4} \operatorname {acos}{\left (c x \right )}}{4} - \frac {b d x \sqrt {- c^{2} x^{2} + 1}}{4 c} - \frac {b e x^{3} \sqrt {- c^{2} x^{2} + 1}}{16 c} - \frac {b d \operatorname {acos}{\left (c x \right )}}{4 c^{2}} - \frac {3 b e x \sqrt {- c^{2} x^{2} + 1}}{32 c^{3}} - \frac {3 b e \operatorname {acos}{\left (c x \right )}}{32 c^{4}} & \text {for}\: c \neq 0 \\\left (a + \frac {\pi b}{2}\right ) \left (\frac {d x^{2}}{2} + \frac {e x^{4}}{4}\right ) & \text {otherwise} \end {cases} \]
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Time = 0.27 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.02 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\frac {1}{4} \, a e x^{4} + \frac {1}{2} \, a d x^{2} + \frac {1}{4} \, {\left (2 \, x^{2} \arccos \left (c x\right ) - c {\left (\frac {\sqrt {-c^{2} x^{2} + 1} x}{c^{2}} - \frac {\arcsin \left (c x\right )}{c^{3}}\right )}\right )} b d + \frac {1}{32} \, {\left (8 \, x^{4} \arccos \left (c x\right ) - {\left (\frac {2 \, \sqrt {-c^{2} x^{2} + 1} x^{3}}{c^{2}} + \frac {3 \, \sqrt {-c^{2} x^{2} + 1} x}{c^{4}} - \frac {3 \, \arcsin \left (c x\right )}{c^{5}}\right )} c\right )} b e \]
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Time = 0.28 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.99 \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\frac {1}{4} \, b e x^{4} \arccos \left (c x\right ) + \frac {1}{4} \, a e x^{4} + \frac {1}{2} \, b d x^{2} \arccos \left (c x\right ) - \frac {\sqrt {-c^{2} x^{2} + 1} b e x^{3}}{16 \, c} + \frac {1}{2} \, a d x^{2} - \frac {\sqrt {-c^{2} x^{2} + 1} b d x}{4 \, c} - \frac {b d \arccos \left (c x\right )}{4 \, c^{2}} - \frac {3 \, \sqrt {-c^{2} x^{2} + 1} b e x}{32 \, c^{3}} - \frac {3 \, b e \arccos \left (c x\right )}{32 \, c^{4}} \]
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Timed out. \[ \int x \left (d+e x^2\right ) (a+b \arccos (c x)) \, dx=\int x\,\left (a+b\,\mathrm {acos}\left (c\,x\right )\right )\,\left (e\,x^2+d\right ) \,d x \]
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